ok so i got...

the half life of carbon-14 is 5730 years, the relation c+(1/2)^ N/5730 is used to calc. the concentration, c, in parts per trillion remaining n years after death determine the carbon concentration in a 11460 year old bone.
please help :)

see above.

it equals .011460 years

To determine the carbon concentration in a 11460-year-old bone using the given equation c+ (1/2)^(N/5730), where c represents the concentration in parts per trillion and N represents the number of years after death, you can follow these steps:

Step 1: Substitute the given values into the equation.
c + (1/2)^(N/5730)

Step 2: Determine the value of N by subtracting the age of the bone (11460 years) from the half-life of carbon-14 (5730 years), as the equation uses the number of years after death.
N = 11460 years - 5730 years
N = 5730 years

Step 3: Plug in the value of N (5730) into the equation.
c + (1/2)^(5730/5730)

Step 4: Simplify the equation using the exponent of 5730/5730, which equals 1.
c + (1/2)^1
c + 1/2

Step 5: Separate the two fractions by finding a common denominator.
c/1 + 1/2

Step 6: Convert 1 to the same denominator as 2 (2/2).
c/1 + 1/2 is equivalent to c/1 + 2/2

Step 7: Combine the fractions.
c/1 + 2/2
c/1 + 2/2 = (c + 2)/2

Therefore, the carbon concentration in a 11460-year-old bone is (c + 2)/2 parts per trillion.