Posted by sandhya on .
A 50g ice cube is added to 110g of water in a 62g aluminum cup. The water and cup initially have a temperature of 23°C. Find the initial temperature of the ice cube such that all of the water is just turned to ice. Use the following specific heats: water = 4186 J/(kg•K), ice = 2090 J/(kg•K), and aluminum = 900 J/(kg•K). The latent heat of fusion for water is 33.5e4 J/kg

physics 
bobpursley,
find the heat needed...
Heatneeded=masswater*c(023)masswater*Lf+massAl*Cal*(023)
Notice this heat is "negative), meaning it was lost. (it is negative heat gained).
now, the heat the ice gained.
massice*Cice*(0Ti)
Now add the heats gained...set to zero.
heat ice gained+heat water(and aluminum) gaied [remember this is negative] =0
solve for Ti 
physics 
tanmay bhoite,
97.93 celcius