Tuesday
May 5, 2015

Homework Help: Chem

Posted by Anonymous on Tuesday, June 29, 2010 at 4:02pm.

25.0 mL of 0.100 M acetic acid (Ka= 1.8 x 10^-5) is titrated with 0.100 M NaOH. Calculate the pH after the addtion of 27.00 mL of 0.100M NaOH.

my work
CH3COOH + H2O <-> H3O^+ + CH3COO^-

25mL x 0.100 mmol/ml = 2.5mmol CH3COOH
27mL x 0.100 mmol/ml = 2.7mmol NaOH

There are more base than acid.... so what do I do?

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