Wednesday
April 16, 2014

Homework Help: Chem

Posted by Anonymous on Tuesday, June 29, 2010 at 4:02pm.

25.0 mL of 0.100 M acetic acid (Ka= 1.8 x 10^-5) is titrated with 0.100 M NaOH. Calculate the pH after the addtion of 27.00 mL of 0.100M NaOH.

my work
CH3COOH + H2O <-> H3O^+ + CH3COO^-

25mL x 0.100 mmol/ml = 2.5mmol CH3COOH
27mL x 0.100 mmol/ml = 2.7mmol NaOH

There are more base than acid.... so what do I do?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - 25.0 mL of 0.100 M acetic acid (Ka= 1.8 x 10^-5) is titrated with 0....
Chem - What is the pH of the resulting solution if 30.00 mL of 0.100M acetic ...
Chemistry - Consider a weak acid-strong base titration in which 25.0 mL of 0.100...
Chemistry - 25 mL 0.1 M acetic acid is titrated with 0.1 M NaOH. Calculate the ...
Chemistry - Calculate the pH at the equivalence point of 25.0 mL of a 0.100 M ...
chemistry - Hello, im having major issues with this problem...I need to find a ...
chemistry - Hello, im having major issues with this problem...A 100.0-mL ...
chem-please help!!!!! - when a 25.0 mL sample of an unknown acid was titrated ...
Chemistry - A volume of 25.0 ml of 0.100 M CH3C02H is titrated with 0.100 M NaOH...
chemistry - A volume of 25.0 mL of 0.100 M CH3CO2H is titrated with 0.100 M NaOH...

Search
Members