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Posted by on Tuesday, June 29, 2010 at 12:08am.

A bothersome feature of many physical measurements is the presence of a background signal (commonly called "noise"). In Part 2.2.4 of the experiment, some light that reflects off the apparatus or from neighboring stations strikes the photometer even when the direct beam is blocked. In addition, due to electronic drifts, the photometer does not generally read 0.0 mV even in a dark room. It is necessary, therefore, to subtract off this background level from the data to obtain a valid measurement. Suppose the measured background level is 4.9 mV. A signal of 20.3 mV is measured at a distance of 29.5 mm and 17 mV is measured at 33 mm. Correct the data for background and normalize the data to the maximum value. What is the normalized corrected value at 33 mm?

  • physics - , Tuesday, June 29, 2010 at 2:45am

    The background-corrected light measurement at 29.5 mm is 20.3 - 4.9 = 15.4 mV

    The corrected light measurement at 33 mm is 17.0 - 4.9 = 12.1 mV

    You need the maximum signal to normalize the data. You have not provided that data.

  • physics - , Thursday, October 16, 2014 at 3:24pm

    12.1/15.4= .785

    ^from drwls's answer above

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