Posted by erin on Monday, June 28, 2010 at 7:44pm.
First find the momentum of the block and embedded bullet right after the collision from conservation of energy:
(1/2) m v^2 = m g h
note m cancels
h = 10 cm = .1 meter
solve above for v
m = 1.5 + .012 kg
now momentum before = momentum after
.012 Vbullet + 0 Vmass = 1.512 v
so
Vbullet = (1.512 / .012) v
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