Posted by STatistic on Monday, June 28, 2010 at 7:22pm.
Prep Courses? Scores for men (nationwide) on the verbal portion of the SAT test are normally distributed with a mean of 509 and a standard deviation of 112. Randomly selected men are given the Columbia review course before taking the SAT test. After the course, a sample of 49 men revealed an average of 535 points and a standard deviation of 90 points. Using a significance level of 0.05, test the claim that the review course students have a mean score greater than or equal to the normal population. (use the 5step method).

statistics  PsyDAG, Tuesday, June 29, 2010 at 11:00am
I don't know what your 5step method is. Here is what I do.
Z = (mean1  mean2)/standard error (SE) of difference between means
SEdiff = √(SEmean1^2 + SEmean2^2)
SEm = SD/√(n1)
If can only calculate one SEm, you can use just that to determine SEdiff.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to that Z score.
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