posted by seth on .
How much limestone (CaCO3) in kilograms would be
required to completely neutralize a lake with a volume of 5.2 x 10^9L . The lake contains 5.0 x 10^-3 moles of H2SO4 per liter?
Multiply the volume of the lake by the concentration, that will give you the moles of sulfuric acid. It will take a similar number of moles of limestone.