v2 - 7v + 5 = 0

A. 2 B.1 C. 0

Ok, I am clueless on this one??

So what is your question?

Are you finding the value of the discriminant, since that is your title?

the discriminant the the part under the square root sign of the quadratic formula, namely
b^2 - 4ac

in your equation,
a = 1
b = -7
c = 5

evaluate.

according to the choices given, you are probably supposed to state whether there are 2, 1 or no real solutions.
Do you not have any notes in your text or class-room notes that tell you about the nature of the roots vs the value of the discriminant??

I just noticed that this same type of question was asked by you and answered by 3 different very competent tutors.

http://www.jiskha.com/display.cgi?id=1277687091

ok thanks, heres the question i will ck out the link

Use the discriminant to determine how many real-number solutions the equation has

This is a quadratic equation of the form ax^2 + bx + c = 0, where a = 1, b = -7, and c = 5. To find the solutions of this quadratic equation, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / (2a)

Plugging in the values, we get:

x = (-(-7) ± sqrt((-7)^2 - 4(1)(5))) / (2(1))
= (7 ± sqrt(49 - 20)) / 2
= (7 ± sqrt(29)) / 2

Therefore, the solutions of the equation are:

x = (7 + sqrt(29)) / 2 and x = (7 - sqrt(29)) / 2

Now we need to determine which of the given options, A, B, or C, matches one of these solutions.

Let's calculate the value of each option:

For option A:
(7 + sqrt(29)) / 2 ≈ 3.79

For option B:
(7 - sqrt(29)) / 2 ≈ 0.21

For option C:
(7 + sqrt(29)) / 2 ≈ 3.79

As you can see, option B is the closest approximation to the second solution, so the answer to the equation v^2 - 7v + 5 = 0 is B.