Tuesday
May 21, 2013

# Homework Help: algebra2

Posted by ann on Sunday, June 27, 2010 at 8:22pm.

kathy bicyles 57 km/h faster than carlos. in the same time it takes carlos to bicyle 36 km. kathy can bicyle 57 km. how fast does each bicyclist travel?

• algebra2 - Henry, Sunday, June 27, 2010 at 10:43pm

Kathy travels 57km/h faster and 21 miles farther(57-36) in the same period
of time. Therefore r*t=d, 57*t=21.
t=21/57=0.3684 hours for each rider.
r*t=d, r*0.3684=36, r=97.7km/h for Carlos. r*0.3684=57, r=154.7km/h for
Kathy.

• algebra2 - Henry, Sunday, June 27, 2010 at 10:43pm

Kathy travels 57km/h faster and 21 miles farther(57-36) in the same period
of time. Therefore r*t=d, 57*t=21.
t=21/57=0.3684 hours for each rider.
r*t=d, r*0.3684=36, r=97.7km/h for Carlos. r*0.3684=57, r=154.7km/h for
Kathy.

• algebra2 - Henry, Sunday, June 27, 2010 at 10:43pm

Kathy travels 57km/h faster and 21 miles farther(57-36) in the same period
of time. Therefore r*t=d, 57*t=21.
t=21/57=0.3684 hours for each rider.
r*t=d, r*0.3684=36, r=97.7km/h for Carlos. r*0.3684=57, r=154.7km/h for
Kathy.

• algebra2 - Henry, Sunday, June 27, 2010 at 10:44pm

Kathy travels 57km/h faster and 21 miles farther(57-36) in the same period
of time. Therefore r*t=d, 57*t=21.
t=21/57=0.3684 hours for each rider.
r*t=d, r*0.3684=36, r=97.7km/h for Carlos. r*0.3684=57, r=154.7km/h for
Kathy.

• algebra2 - Henry, Sunday, June 27, 2010 at 10:44pm

Kathy travels 57km/h faster and 21 miles farther(57-36) in the same period
of time. Therefore r*t=d, 57*t=21.
t=21/57=0.3684 hours for each rider.
r*t=d, r*0.3684=36, r=97.7km/h for Carlos. r*0.3684=57, r=154.7km/h for
Kathy.

• algebra2 - Henry, Sunday, June 27, 2010 at 10:51pm

Kathy travels 57km/h faster and 21 miles farther(57-36) in the same period
of time. Therefore r*t=d, 57*t=21.
t=21/57=0.3684 hours for each rider.
r*t=d, r*0.3684=36, r=97.7km/h for Carlos. r*0.3684=57, r=154.7km/h for
Kathy.

• algebra2 - Henry, Sunday, June 27, 2010 at 10:51pm

Kathy travels 57km/h faster and 21 miles farther(57-36) in the same period
of time. Therefore r*t=d, 57*t=21.
t=21/57=0.3684 hours for each rider.
r*t=d, r*0.3684=36, r=97.7km/h for Carlos. r*0.3684=57, r=154.7km/h for
Kathy.

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