Posted by Lisa D on Sunday, June 27, 2010 at 7:58pm.
w2  2w + 2 = 0
Use the discriminant to determine how many realnumber solutions the equation has
A.2
B.1
C.0

Equation  Jen, Sunday, June 27, 2010 at 8:10pm
The discriminant is b^24ac. For the equation you posted, a=1 (the coefficient on w^2), b=2, and c=2. Plug those numbers in. If the number you get is positive, there are 2 real number solutions. If you get zero, there is 1 solution. If you get a negative number, there are no solutions. Post your answer if you want it checked.

Equation  bobpursley, Sunday, June 27, 2010 at 8:24pm
Actually, if you get a negative discriminant, you get no real solutions, but insteady, you get complex (in the imaginary domain) solutions, that in general, are valid.
eg. x^2+0x+1=0
the discriminate is sqrt(4)
and in fact, then the solution is
x= + i

Equation  Lisa D, Sunday, June 27, 2010 at 9:11pm
Is the answer 0 not sure if this is correct.

Equation  Jen, Monday, June 28, 2010 at 1:02am
Show me your work. You have to plug in the numbers.
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