q+5 + q-2 = 7/3
_____________
3 2
the 2 is supposed to be below q-2
Donna, you have to work on formatting them like how you did here on your 7:14 post so we can understand them.
y-6= 2/7
____
y+4
To solve the given equation:
1. Start by multiplying the entire equation by the common denominator of 3 and 2, which is 6. This step is necessary to eliminate the fractions from the equation.
(6) * (q+5) + (6) * (q-2) = (6) * (7/3) / (6) * (6/1)
6(q+5) + 6(q-2) = 7 * 6 / 3 * 6
6q + 30 + 6q - 12 = 42 / 18
2. Simplify the equation by combining like terms on both sides:
12q + 18 = 42 / 18
3. Next, isolate the variable term by subtracting 18 from both sides of the equation:
12q + 18 - 18 = 42 / 18 - 18
12q = 42 / 18 - 18
4. Simplify the right side of the equation:
12q = 42 / 18 - 18
12q = 7 / 3 - 18
12q = 7 / 3 - (18 * 3) / 3
12q = (7 - 54) / 3
12q = -47 / 3
5. Finally, divide both sides of the equation by 12 to solve for q:
12q / 12 = -47 / 3 / 12
q = -47 / (3 * 12)
q = -47 / 36
Therefore, the solution to the equation q+5 + q-2 = 7/3 / 3/2 is q = -47/36.