Posted by donna on Sunday, June 27, 2010 at 7:04pm.
y6=2
y+4 _= help
7

algebra2  Jen, Sunday, June 27, 2010 at 7:05pm
Please rewrite. Should this say y6=2 and y+4=7?

algebra2  donna, Sunday, June 27, 2010 at 7:09pm
y6
bottom number y+4 and then 2 with a lind on bottom and 7

algebra2  donna, Sunday, June 27, 2010 at 7:12pm
its suppposed to be y=

algebra2  Jen, Sunday, June 27, 2010 at 7:13pm
That doesn't make any sense. Sorry, but I don't know what you're trying to say.

algebra2  donna, Sunday, June 27, 2010 at 7:14pm
y6= 2/7
____
y+4

algebra2  Jen, Sunday, June 27, 2010 at 7:38pm
For problems like these, you want to cross multiply. 7(y6)=2(y+4), 7y42=2y+8, 7y=2y+50, 5y=50, y=10. You can plug that in for a check and you get 4/14, whcih reduces to 2/7, so it works.
Answer This Question
Related Questions
 Algebra2  23x58=8
 algebra2  (x5)^1/3 4=2
 Algebra2  Help? f(x)=5 ; x=3,2,1,0,1,2,3
 algebra2  s2/2s1/5=1/4
 algebra2  if a=5 and b=3 4a3b
 algebra2  2x+3=7
 algebra2  5(6+2).2
 algebra2  5/21.(7/15)
 Algebra2  If f = (1, 2), (2, 3), (3, 4), (4, 5), g = (1, 2), (3, 3), (5, 5...
 Algebra2  Help ? 1. x3x^1/2+2=0
More Related Questions