Posted by **donna** on Sunday, June 27, 2010 at 7:04pm.

y-6=2

y+4 _= help

7

- algebra2 -
**Jen**, Sunday, June 27, 2010 at 7:05pm
Please re-write. Should this say y-6=2 and y+4=7?

- algebra2 -
**donna**, Sunday, June 27, 2010 at 7:09pm
y-6

bottom number y+4 and then 2 with a lind on bottom and 7

- algebra2 -
**donna**, Sunday, June 27, 2010 at 7:12pm
its suppposed to be y=

- algebra2 -
**Jen**, Sunday, June 27, 2010 at 7:13pm
That doesn't make any sense. Sorry, but I don't know what you're trying to say.

- algebra2 -
**donna**, Sunday, June 27, 2010 at 7:14pm
y-6= 2/7

____

y+4

- algebra2 -
**Jen**, Sunday, June 27, 2010 at 7:38pm
For problems like these, you want to cross multiply. 7(y-6)=2(y+4), 7y-42=2y+8, 7y=2y+50, 5y=50, y=10. You can plug that in for a check and you get 4/14, whcih reduces to 2/7, so it works.

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