Posted by **donna** on Sunday, June 27, 2010 at 7:04pm.

y-6=2

y+4 _= help

7

- algebra2 -
**Jen**, Sunday, June 27, 2010 at 7:05pm
Please re-write. Should this say y-6=2 and y+4=7?

- algebra2 -
**donna**, Sunday, June 27, 2010 at 7:09pm
y-6

bottom number y+4 and then 2 with a lind on bottom and 7

- algebra2 -
**donna**, Sunday, June 27, 2010 at 7:12pm
its suppposed to be y=

- algebra2 -
**Jen**, Sunday, June 27, 2010 at 7:13pm
That doesn't make any sense. Sorry, but I don't know what you're trying to say.

- algebra2 -
**donna**, Sunday, June 27, 2010 at 7:14pm
y-6= 2/7

____

y+4

- algebra2 -
**Jen**, Sunday, June 27, 2010 at 7:38pm
For problems like these, you want to cross multiply. 7(y-6)=2(y+4), 7y-42=2y+8, 7y=2y+50, 5y=50, y=10. You can plug that in for a check and you get 4/14, whcih reduces to 2/7, so it works.

## Answer this Question

## Related Questions

- algebra2 - (x-5)^1/3 -4=-2
- Algebra2 - Help? f(x)=5 ; x=3,-2,-1,0,1,2,3
- algebra2 - s-2/2-s-1/5=1/4
- algebra2 - if a=5 and b=-3 4a-3b
- algebra2 - 2x+3=7
- algebra2 - 5-(6+2).2
- algebra2 - 5/21.(-7/15)
- Algebra2 - If f = (1, 2), (2, 3), (3, 4), (4, 5), g = (1, -2), (3, -3), (5, -5...
- Algebra2 - Help ? 1. x-3x^1/2+2=0
- Algebra2 - Help? 1.2x^2/3+5^1/3=12 2. 6x^6/3-5x^1/3-6=0