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September 17, 2014

September 17, 2014

Posted by **jc** on Sunday, June 27, 2010 at 4:16pm.

- statistics -
**PsyDAG**, Monday, June 28, 2010 at 10:57am68% are approximately within mean ± 1 SD

Z = ±1 = (score - mean)/SEm

SEm = SD/√(n-1) = approx. SD/10

Insert values in above Z equation to get scores.

- statistics -
**Tempie**, Monday, June 28, 2010 at 3:29pmconsider a normal distribution with mean 27 and standard deviation 6. What is the probability a value selected at random from this distribution is great than 27?

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