Posted by jc on Sunday, June 27, 2010 at 4:16pm.
68% are approximately within mean ± 1 SD
Z = ±1 = (score - mean)/SEm
SEm = SD/√(n-1) = approx. SD/10
Insert values in above Z equation to get scores.
consider a normal distribution with mean 27 and standard deviation 6. What is the probability a value selected at random from this distribution is great than 27?
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