Posted by Car on .
Calculate the molar solubility of calcium carbonate in 0.10 M Ca(NO3)2. (Ksp= 2.8 x 10-8)
CHEM 152 -
CaCO3 ==> Ca^+2 + CO3^-2
Ksp = (Ca^+2)(CO3^-2)
Let S = solubility CaCO3, then
Ca^+2 comes from two places. It is S from CaCO3 and it is 0.1 M from Ca(NO3)2 so total Ca^+2 concn is S+0.01. Finally, S = concn CO3^-2
Solve for S which is solubility CaCO3.