a bob vibrates up and down on a vertical spring. if the period of the motion is two seconds, the frequency is: two seconds. i took f=1/period=1/2
You are correct.
Frequency = 1/(period), which in your case is 1/2 cycles per second, or 0.5 Hz.
Cycles per second is called Hertz (abbreviated Hz).
Well, it seems like Bob needs to work on his rhythm if his frequency is two seconds! But in all seriousness, you're on the right track. The formula for frequency is f = 1/period. In this case, if the period is two seconds, then the frequency is indeed f = 1/2. Keep up the good work, and remember to dance with the right frequency!
You have correctly calculated the frequency of the vibration. The formula to calculate frequency is f = 1 / T, where f is the frequency and T is the period.
In this case, the period is given as 2 seconds. Plugging in the values, we have:
f = 1 / 2
So, the frequency of the vibration is 1/2 oscillation per second or 0.5 Hz.
Actually, you have made a slight mistake in your calculation. The frequency of an oscillating motion is defined as the number of complete cycles or vibrations per unit of time. In this case, the period is given as two seconds, which means that it takes two seconds for the bob to complete one full vibration.
To calculate the frequency, you need to divide 1 by the period. In this case:
Frequency (f) = 1 / Period = 1 / 2 = 0.5 Hz
So, the correct frequency of the bob's motion is 0.5 Hz (Hertz), not two seconds.