Posted by **keith** on Saturday, June 26, 2010 at 1:51pm.

Equation for a line that passes through (6,26) and has a slope of 3

Equation for a line that passes through the points (5,5) and (10,20)

Equation for a line that passes through (9,25) and has a slope of -3.

Equation for a line that passes through (1,) and is perpendicular to the line 4x+6y=18.

Equatuion for a cirle with a radius of 4 and a midpoint at (2,2).

- Try them first -
**Damon**, Saturday, June 26, 2010 at 2:21pm
I already know how to do these. Try them yourself first and show me where you got stuck.

The first three can all be done substituting in

y = m x + b

where m is the slope.

For the fourth one, put the equation in form y = m x + b first

Then find m' = -1/m

That is the slope of a line perpendicular to the original one

then do y = m'x + b and substitute in your point, which you forgot to type the y coordinate for.

In the last one a circle equation is of form

(x-k)^2 + (y-h)^2 = r^2

where (k,h) is the center and r is the radius.

- mat 101 -
**Anonymous**, Sunday, October 14, 2012 at 6:05pm
y=mx+b

26=3(6)+b

b=26/18

b=13/9

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