Given a rectangular prism with dimensions w = 3, l= 4, and h = 6. If you created a second rectangular prism with the length doubled but the height halved (and the width stays the same), which would be the relation of the second volume to the first volume?

What do you find when you actually solve these problems?

i don't kno how to solve them i nvr did geometry

If you double one dimension, halve another, and keep the third the same, wouldn't the volume be identical?

http://www.aaastudy.com/geo.htm#topic25

This is a 3 dimensional scaling problem.

If you double measurements in one direction and halve them in another you do not change the volume.
3*4*6 = 72
3*8*3 = 72

note

3*4(2)*6(1/2) =3*4*6

so The second volume would be the same as that of the first volume?

I have no idea. I was looking for the same answer. Is there anyone out there that can help me?

Given a rectangular prism with dimensions w = 3, l = 4, and h = 6. If you created a second rectangular prism with the length doubled but the height halved (and the width stays the same), which would be the relation of the second volume to the first volume?