rearrange the equation T = 2pi(l/g)^(1/2) in the form of y=mx+c where T = dependent variable, L = independent variable, and 2pi and g = constant.
You want to put a second degree equation in the form of a linear equation?
T is proportional to sqrt of L, not L.
what about the gradient and intercept at y-axis?
To rearrange the equation T = 2π(l/g)^(1/2) in the form of y = mx + c, where T is the dependent variable, L is the independent variable, and 2π and g are constants, we need to isolate T on one side of the equation and express it in terms of L.
First, let's begin by squaring both sides of the equation to eliminate the square root:
T^2 = (2π(l/g))^(1/2)^2
T^2 = 2π(l/g)
Next, let's multiply both sides of the equation by g:
gT^2 = 2πl
Now, let's divide both sides of the equation by 2π:
gT^2 / (2π) = l
Finally, we can rewrite the equation in the form of y = mx + c by substituting T with y and l with L:
g(y^2 / (2π)) = L
Rearranging further, we can express it as:
y^2 = (2πL / g)
Thus, the given equation T = 2π(l/g)^(1/2) rearranges to the form y = mx + c as y^2 = (2πL / g), where T is the dependent variable, L is the independent variable, and 2π and g are constants.