Tuesday

September 2, 2014

September 2, 2014

Posted by **sha** on Wednesday, June 23, 2010 at 10:01pm.

- finitemath -
**MathMate**, Thursday, June 24, 2010 at 8:33amEquate total selling price of mixture to total selling price of components. Solve for weight of cashews.

Let

x=weight of cashews to be added

Total price of mixture

= 3(30+x)

Total price of components

= 30*1.5 + 5x

Equate and solve for x:

3(30+x) = 30*1.5 + 5x

Isolate x and solv

5x-3x = 3(30)-30(1.5)

2x = 45

x = 22.5 lbs

- finitemath -
**sha**, Thursday, June 24, 2010 at 9:57amthanks a million!

**Answer this Question**

**Related Questions**

college algebra - A store sells cashews for $5.00 per pound and peanuts for $1....

Math Word Problem - Cashews sell for $4.00 per pound and peanuts for $1.50 per ...

Math - A manager bought 12 pounds of peanuts for $30. He wants to mix $5 per ...

Math - Peanuts sell for $3.00 per pound. Cashews sell for $6.00 per pound. How ...

algebra - A store sells mixtures of almonds and cashews for $6.50 per pound. ...

college - If cashews cost $5.00 per pound and peanuts cost $1.50 per pound how ...

algebra - The manager of a bulk foods establishment sells a trail mix for $6 per...

Algebra Word Problem - Peanuts are selling for $2 per pound, and cashews are ...

MATH (Algebra) - All-mixed-up nut shop sells mix consisting of cashews and ...

Math - A grocery store wants to make a mixture of nuts consisting of cashews and...