Posted by **sha** on Wednesday, June 23, 2010 at 10:01pm.

a store sells cashews for $5.00 per pound and peanuts for $1.50 per pound. the manager decides to mix 30 pounds of peanuts with some cashews and sell the mixture for $3.00 per pound. how many pounds of cashews should be mixed with the peanuts so that the mixture will produce the same revenue as would selling the nuts separately?

- finitemath -
**MathMate**, Thursday, June 24, 2010 at 8:33am
Equate total selling price of mixture to total selling price of components. Solve for weight of cashews.

Let

x=weight of cashews to be added

Total price of mixture

= 3(30+x)

Total price of components

= 30*1.5 + 5x

Equate and solve for x:

3(30+x) = 30*1.5 + 5x

Isolate x and solv

5x-3x = 3(30)-30(1.5)

2x = 45

x = 22.5 lbs

- finitemath -
**sha**, Thursday, June 24, 2010 at 9:57am
thanks a million!

- finitemath -
**Anonymous**, Thursday, November 13, 2014 at 1:33pm
The grocery store sells kumquats for $3.75 a pound and Asian pears for $2.25 a pound. Write an equation in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $14.

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