Posted by **sha** on Wednesday, June 23, 2010 at 8:25pm.

dimension of a floor; the perimeter of a rectangular floor is 90ft. find the dimensions of the floor if the length is twice the width

- fintemath -
**Ms. Sue**, Wednesday, June 23, 2010 at 9:08pm
P = 2L + 2W

90 = 4W + 2W

90 = 6W

15 = W

Check:

15 + 15 + 30 + 30 = 90

- fintemath -
**sha**, Wednesday, June 23, 2010 at 9:24pm
i know 90 is the perimeter but where did the 4W + 2W come from?

- finitemath -
**Ms. Sue**, Wednesday, June 23, 2010 at 9:25pm
This is the formula for a perimeter.

P = 2L + 2W

Your problem states that the length is twice the width. Therefore, L = 2W

- fintemath -
**sha**, Wednesday, June 23, 2010 at 9:30pm
what happened to 2L? sorry for my dumb question.

- fintemath -
**sha**, Wednesday, June 23, 2010 at 9:34pm
oh nevermind.. i got it. thanks for helping me Ms. Sue (:

- fintemath -
**Ms. Sue**, Wednesday, June 23, 2010 at 9:40pm
You're welcome, Sha.

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