function y=4-2sin(2t+pi/2), where t is measured in radians. choose one option which gives the value of the function when t=pi radians.

a)0 b)1 c)2 d)4 e)pi/4 e)pi/4 f)pi/2 g)pi h)2pi

y=4-2sin(2t+pi/2) , when t= π

y = 4 - 2sin(2π + π/2) = 4 - 2sin(5π/2)
= 4 - 2sin(π/2) , since π/2 and 5π/2 are coterminal angles.
= 4 - 2
= 2

Cheers Reiny

To find the value of the function when t = pi radians, we need to substitute pi into the expression for y.

Given the function y = 4 - 2sin(2t + pi/2), we can substitute pi for t:

y = 4 - 2sin(2(pi) + pi/2)
= 4 - 2sin(2pi + pi/2)
= 4 - 2sin(3pi/2)

Now, we need to evaluate sin(3pi/2).

In the unit circle, the point corresponding to 3pi/2 (270 degrees) will have a y-coordinate of -1, since it is located at the bottom of the circle.

Therefore, sin(3pi/2) = -1.

Substituting this back into the expression for y:

y = 4 - 2(-1)
= 4 + 2
= 6

So, when t = pi radians, the value of the function y is 6.

Thus, the correct option is not provided. The correct option would be 6.