Posted by sar on Tuesday, June 22, 2010 at 11:49am.
You know the length of the meter stick, one meter (100 cm).
First we need to find the center of gravity. We know that is at 49.7 am because that is where it balances all by itself.
now we put the 50 g mass on,
take moments about the 39.2 balance point.
50 (39.2 - 10) = m (49.7-39.2)
solve for m
Related Questions
Physics* - A meter stick is found to balance at the 49.7-cm mark when placed on ...
Physics - This is how the problem starts out: A meter stick is placed with the ...
physics - Two metal disks are taped to a meterstick. The mass of the meterstick ...
Physics - You have a 120-g meterstick. Where should you place the meterstick ...
physics - if a 200-g mass is placed at the 20-cm mark (30 cm from the fulcrum), ...
physic - a uniform meter stick of mass 100g is pivoted about the 30 cm mark. a ...
physics - A meter stick balances horizontally on a knife-edge at the 50.0 cm ...
Physics - A meter stick balances horizontally on a knife-edge at the 50.0 cm ...
Physics - A uniform meter stick balances on a fulcrum placed at the 40 cm mark ...
Physics - A uniform meter stick balances on a fulcrum placed at the 40 cm mark ...
For Further Reading
