Total plasma volume is important in determining the required plasma component in blood replacement theory for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that sample of 61 male firefighters are tested and that they have a plasma volume sample mean of ml/kg (milliliters of plasma per kilogram body weight). Assume that ml/kg for the distribution of blood plasma. Find the margin of error for 98% confidence level of the population mean blood plasma volume in male firefighters. Round your answer to two decimal places. 2.24 ml/kg
51.90 ml/kg
0.94 ml/kg
0.29 ml/kg
0.34 ml/kg
You are missing values of mean and SD.
98% interval = mean ±2.33 SE
SE (Standard error) = SD/√(n-1)
Z = ±2.33 = (score - mean)/SE
35.5
To find the margin of error for a 98% confidence level of the population mean blood plasma volume in male firefighters, we can use the formula:
Margin of Error = Critical Value * Standard Error
First, let's find the critical value. For a 98% confidence level, we need to find the z-score that corresponds to the area between the mean and the confidence level on a standard normal distribution.
The area between the mean and the confidence level is (1 - 0.98) / 2 = 0.01. Looking up this area in a standard normal distribution table or using a calculator, we find that the z-score corresponding to this area is approximately 2.33.
Next, we need to find the standard error. The standard error measures the variability of the sample mean. It is calculated by dividing the standard deviation of the sample by the square root of the sample size.
Since the problem does not provide the standard deviation or the sample size, we are unable to calculate the standard error and, consequently, the margin of error.
Thus, it is not possible to determine the margin of error for 98% confidence level using the given information.