Posted by Jack on Sunday, June 20, 2010 at 11:09am.
Z = (score - mean)/SD
Z = (58.5-62)/ 3.5 = -1
Z = (72.5-62)/3.5 = 3
It goes from one standard deviation below the mean to 3 above.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to those Z scores.
my answer is equals 15.7 is this correct
Assuming that the heights of college women are normally distributed with mean 62 inches and standard deviation 3.5 inches, what percentage of women are between 58.5 inches and 72.5 inches?
a. 13.6%
b. 84.0%
c. 97.6%
d. 34.1%
e. 15.7%
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