Posted by **Santha** on Saturday, June 19, 2010 at 6:32pm.

I HAVE AN EXAM REVIEW QUESTION AND I REALLY NEED HELP.

An airplane has an air speed of 330km/h and is heading in a direction of N30E when it encounters a wind from the north. The resultant ground velocity has a direction of N40E. How long does it take for the plane to travel 960km.

- Calculus - URGENT EXAM -
**Reiny**, Saturday, June 19, 2010 at 7:57pm
Did you make a diagram?

My vector diagram has angles 10°, 30°, and 140° with the longest sides as 330.

so the side across the 30° represents the ground velocity of the plane, let it be x

By the sine law

x/sin30 = 330/sin140

x = 256.69

so the actual groundspeed is 269.69 km/h, then to go 960 km would take

960/269.69 hours or 3.74 hours

or 3 hours and 44 minutes and 23.5 seconds

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