Posted by **Artis** on Saturday, June 19, 2010 at 1:01pm.

Can you give me step by step instruction on how to solve this problem

Helium is pumped into a spherical balloon at a constant rate of 4cubic feet per second. How fast is the radius increasing after 3 minutes? At what time (if any) is the radius increasing at a rate of 120 feet per second?

- math -
**Reiny**, Saturday, June 19, 2010 at 5:47pm
given: dV/dt = 4 ft^3/sec

V= (4/3)πr^3

dV/dt = 4πr^2 dr/dt

3 min = 180 sec

So after 3 min, V = 180(4) or 720 ft^3

720 = (4/3)πr^3

solve for r, then sub into

dV/dt = 4πr^2 dr/dt

solve for dr/dt

For the second part, replace dr/dt by 120

That way you will be able to solve for r

Using that r, find the Volume,

divide that volume by 4 to get the number of seconds it took to fill it that much.

## Answer this Question

## Related Questions

- Math - Please help. I have the answers to these problems but I'd like to know ...
- math-calculus - A spherical party balloon is being inflated with helium pumped ...
- Calculus - A spherical party balloon is being inflated with helium pumped in at ...
- calculus - Air is being pumped into a spherical balloon so that its volume ...
- Calculus - Air is being pumped into a spherical balloon so that its volume ...
- calculus - gas is pumped into a spherical balloon at the rate of 1 cubic feet ...
- math - Air is pumped into a balloon such that its volume increases at the rate ...
- Calculus - Air is being pumped into a spherical balloon so that its volume ...
- calc - Air is being pumped into a spherical balloon so that its volume increases...
- calculus - Air is being pumped into a spherical balloon so that its volume ...