Wednesday

July 23, 2014

July 23, 2014

Posted by **Artis** on Saturday, June 19, 2010 at 1:01pm.

Helium is pumped into a spherical balloon at a constant rate of 4cubic feet per second. How fast is the radius increasing after 3 minutes? At what time (if any) is the radius increasing at a rate of 120 feet per second?

- math -
**Reiny**, Saturday, June 19, 2010 at 5:47pmgiven: dV/dt = 4 ft^3/sec

V= (4/3)πr^3

dV/dt = 4πr^2 dr/dt

3 min = 180 sec

So after 3 min, V = 180(4) or 720 ft^3

720 = (4/3)πr^3

solve for r, then sub into

dV/dt = 4πr^2 dr/dt

solve for dr/dt

For the second part, replace dr/dt by 120

That way you will be able to solve for r

Using that r, find the Volume,

divide that volume by 4 to get the number of seconds it took to fill it that much.

**Related Questions**

math-calculus - A spherical party balloon is being inflated with helium pumped ...

calculus - gas is pumped into a spherical balloon at the rate of 1 cubic feet ...

Chemistry - Please tell me which Gas Law equation to use to figure out this ...

Calculus - A spherical party balloon is being inflated with helium pumped in at ...

calculus - air is being pumped into a spherical balloon at a rate of 8 cm^3/min...

math - Air is pumped into a balloon such that its volume increases at the rate ...

calculus - Air is being pumped into a spherical balloon so that its volume ...

calculus - Air is being pumped into a spherical balloon so that its volume ...

Calculus - Air is being pumped into a spherical balloon so that its volume ...

Physics - A spherical helium filled balloon is attached to a string that is ...