Saturday
October 25, 2014

Homework Help: maths - trigonometry

Posted by anonymous on Saturday, June 19, 2010 at 11:56am.

I've asked about this same question before, and someone gave me the way to finish, which I understand to some extent. I need help figuring out what they did in the second step though. How they got to the third step from the second.

[sinx + tanx]/[cosx + 1] = tanx

LS=[sinx+tanx]/[cosx+1]
=[sinx+tanx]/[cox+(cosx/cosx)]

makes sense so far, but I don't know how they got from here to the next one

=[sinxcosx-sinx+sinx-sinx/cosx]/[cosx-1]

or to the next

=[(sinxcos^2x-sinx)/cosx]/[cos^2x-1]

but from there I understand

=[sinx(cos^2x-1)/cosx]*[1/cos^2x-1]
=sinx/cosx
=tanx
=RS

Help?

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