Posted by **Mark** on Saturday, June 19, 2010 at 9:09am.

A square has an area of S^2 and a regular hexagon has a perimeter of T. If p is the perimeter of the square and h is a side of the hexagon, then find h+p in terms of S and T.

- Maths -
**Henry**, Thursday, June 24, 2010 at 6:17pm
SQUARE: A=S^2=S.S, Perimeter=P=4S.

REGULAR HEXAGON: Perimeter=T=6h,h=T/6.

h+P=T/6+4S.

- Maths -
**Lucy**, Sunday, February 24, 2013 at 3:00am
square A=S^2, P=p (side of the square must be S, p=4(S))

Regular Hexagon P=T and side=h (side is total perimeter divided by the sides of the hexagon (6))

therefore, h+p in terms of S and T.

(P/6)+ 4S

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