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November 27, 2014

November 27, 2014

Posted by **Mark** on Saturday, June 19, 2010 at 9:09am.

- Maths -
**Henry**, Thursday, June 24, 2010 at 6:17pmSQUARE: A=S^2=S.S, Perimeter=P=4S.

REGULAR HEXAGON: Perimeter=T=6h,h=T/6.

h+P=T/6+4S.

- Maths -
**Lucy**, Sunday, February 24, 2013 at 3:00amsquare A=S^2, P=p (side of the square must be S, p=4(S))

Regular Hexagon P=T and side=h (side is total perimeter divided by the sides of the hexagon (6))

therefore, h+p in terms of S and T.

(P/6)+ 4S

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