Post a New Question


posted by .

A square has an area of S^2 and a regular hexagon has a perimeter of T. If p is the perimeter of the square and h is a side of the hexagon, then find h+p in terms of S and T.

  • Maths -

    SQUARE: A=S^2=S.S, Perimeter=P=4S.

    REGULAR HEXAGON: Perimeter=T=6h,h=T/6.

  • Maths -

    square A=S^2, P=p (side of the square must be S, p=4(S))
    Regular Hexagon P=T and side=h (side is total perimeter divided by the sides of the hexagon (6))
    therefore, h+p in terms of S and T.
    (P/6)+ 4S

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question