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Maths

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A square has an area of S^2 and a regular hexagon has a perimeter of T. If p is the perimeter of the square and h is a side of the hexagon, then find h+p in terms of S and T.

  • Maths - ,

    SQUARE: A=S^2=S.S, Perimeter=P=4S.

    REGULAR HEXAGON: Perimeter=T=6h,h=T/6.
    h+P=T/6+4S.

  • Maths - ,

    square A=S^2, P=p (side of the square must be S, p=4(S))
    Regular Hexagon P=T and side=h (side is total perimeter divided by the sides of the hexagon (6))
    therefore, h+p in terms of S and T.
    (P/6)+ 4S

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