maths  trigonometry
posted by anonymous on .
I have my maths exam on Tuesday and cannot remember how to do trigonometric identities at all. I was so sure, but now I'm not. I asked a similar question earlier, but I still don't quite understand. Please give me stepbystep instructions?
[sinx + tanx] / [cosx +1] = tanx

I just got done with thi stuff and these are the formulas that helped me with alot.
tan(angle)=opposite/adjacent
coa(angle)=adjacent/hypotenuse
sin(angle)=opposite/hypotenuse
Is this what your asking for? 
that's sort of a tricky one,
[sinx + tanx] / [cosx +1] = tanx
LS = (sinx + tanx)/(cosx+1) [(cosx1)/cosx1)]
= (sinxcosx  sinx + sinx  sinx/cosx)/(cos^2x  1)
= [ (sinxcos^2x  sinx)/cosx]/(cos^2x  1)
= sinx[cos^2x  1)/cosx] / (cos^2x  1)
= sinx/cosx
= tanx
= RS