Posted by anonymous on .
I'm reviewing for my exams, and I was sure that I was comfortable with solving trigonometric identities, but now that I'm looking at ones on my review, I'm not so sure. Could someone please show me, step by step, how to answer one?
[cos^2theta] / [1 +2sintheta 2sin^2theta]
is equal to
[1 +sintheta] / [1 +3sintheta]
Thanks in advance :)

maths 
Damon,
I think you have a typo  see my 3 below
[1s^2] / [3s^2 2s 1]
(not 2s^22s1)
[(s1)(s+1)] / [ (s1) (3s+1) ]