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December 22, 2014

December 22, 2014

Posted by **anonymous** on Friday, June 18, 2010 at 6:02pm.

[cos^2theta] / [1 +2sintheta -2sin^2theta]

is equal to

[1 +sintheta] / [1 +3sintheta]

Thanks in advance :)

- maths -
**Damon**, Friday, June 18, 2010 at 7:17pmI think you have a typo - see my 3 below

-[1-s^2] / [3s^2 -2s -1]

(not 2s^2-2s-1)

[(s-1)(s+1)] / [ (s-1) (3s+1) ]

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