Posted by student on .
an asteroid orbits the sun at a constant distance of 4.44e+11 meters, the suns mass is 1.00*10^30kg, what is the orbital speed of the asteroid? Please explain step by step thanks

physics/orbital speed 
tchrwill,
An asteroid orbits the sun at a constant distance of 4.44e+11 meters, the suns mass is 1.00*10^30kg, what is the orbital speed of the asteroid? Please explain step by step thanks
At first glance, your problem statement is subject to interpretation.
1Is the 4.44e^11 distance meant to mean
…(4.44e)^11 = 7.9150x10^11 meters
…or 4.44(e^11) = 265,841 meters?
2Is the distance, r, meant to be from the center of the sun or the surface of the sun?
3—If the center of the sun, the distance can only be 7.9150x10^11 meters.
….If the surface of the sun, either can apply.
4Providing the mass of the sun implies that you need to compute the gravitational constant of the sun = GM where G = the universal gravitational constant, 6.676259x10^11m^3/kg.sec^2 and M = the mass of the sun.
5You give the mass of the sun as 1.00x10^30kg, when, in reality, it is closer to 2.0x10^30 or
1.989157x10^30kg.
5The actual gravitational constant of the sun is µ = 1.327283x10^20m^3/sec.^2.
Once you have sorted out which of the quantities you intend to use, the velocity required to maintain a circular orbit around the sun may be computed from the following:
Vc = sqrt(µ/r) 
physics/orbital speed 
student,
thnk you so much.!