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August 1, 2015

August 1, 2015

Posted by **student** on Thursday, June 17, 2010 at 5:52pm.

- physics/orbital speed -
**tchrwill**, Saturday, June 19, 2010 at 10:41amAn asteroid orbits the sun at a constant distance of 4.44e+11 meters, the suns mass is 1.00*10^30kg, what is the orbital speed of the asteroid? Please explain step by step thanks

At first glance, your problem statement is subject to interpretation.

1---Is the 4.44e^11 distance meant to mean

…(4.44e)^11 = 7.9150x10^11 meters

…or 4.44(e^11) = 265,841 meters?

2---Is the distance, r, meant to be from the center of the sun or the surface of the sun?

3—If the center of the sun, the distance can only be 7.9150x10^11 meters.

….If the surface of the sun, either can apply.

4---Providing the mass of the sun implies that you need to compute the gravitational constant of the sun = GM where G = the universal gravitational constant, 6.676259x10^-11m^3/kg.sec^2 and M = the mass of the sun.

5---You give the mass of the sun as 1.00x10^30kg, when, in reality, it is closer to 2.0x10^30 or

1.989157x10^30kg.

5---The actual gravitational constant of the sun is µ = 1.327283x10^20m^3/sec.^2.

Once you have sorted out which of the quantities you intend to use, the velocity required to maintain a circular orbit around the sun may be computed from the following:

Vc = sqrt(µ/r)

- physics/orbital speed -
**student**, Sunday, June 20, 2010 at 3:43amthnk you so much.!