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September 18, 2014

September 18, 2014

Posted by **Jacqueline** on Wednesday, June 16, 2010 at 8:15pm.

what is the lenght of AD to the nearest tenth of a centimeter?

- geometry -
**Damon**, Wednesday, June 16, 2010 at 9:02pm3,4,5 right trisangle so

hypotenuse = 10

Draw it and note similar triangles ABC, CBD, ACD

call AD = x

then BD = 10-x

the altitude CD = sqrt (36-x^2)

the altitude CD = sqrt (64 -(10-x)^2)

so

36-x^2 = 64 - (10-x)^2

36 - x^2 = 64 - ( 100 -20 x + x^2)

36 - x^2 = -36 + 20 x - x^2

72 = 20 x

x = 72/20 = 3.6

- geometry -
**bob**, Monday, May 26, 2014 at 3:44pmur mom

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