Posted by **Jacqueline** on Wednesday, June 16, 2010 at 8:15pm.

In the diagram below, the length of the legs AC and BC of right triangle ABC are 6cm and 8cm, respectively.Altitude CD is drawm to the hypotenuse of triangle ABC.

what is the lenght of AD to the nearest tenth of a centimeter?

- geometry -
**Damon**, Wednesday, June 16, 2010 at 9:02pm
3,4,5 right trisangle so

hypotenuse = 10

Draw it and note similar triangles ABC, CBD, ACD

call AD = x

then BD = 10-x

the altitude CD = sqrt (36-x^2)

the altitude CD = sqrt (64 -(10-x)^2)

so

36-x^2 = 64 - (10-x)^2

36 - x^2 = 64 - ( 100 -20 x + x^2)

36 - x^2 = -36 + 20 x - x^2

72 = 20 x

x = 72/20 = 3.6

- geometry -
**bob**, Monday, May 26, 2014 at 3:44pm
ur mom

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