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April 18, 2014

April 18, 2014

Posted by **John** on Wednesday, June 16, 2010 at 7:12pm.

f(x)= sin x/x^2 - 9

That is, state where is it continuous/discontinuous and why.

Here was my original answer.

sinx is cont. because it's a trig function. It's cont. at -2pi, pi, -pi, and 2pi.

x^2 is cont. because it's raised to a rational power.

-9 is cont. because it's a polynomial.

He then put x= -3 + 3? at the bottom of my work.

I'm guessing that's where it's discontinuous. So f(x) is discontinuous where x= -3 and 3

- Calculus- continuity -
**MathMate**, Wednesday, June 16, 2010 at 7:41pmf(x)= sin x/(x^2 - 9)

Your answer is correct, but unfortunately incomplete.

In the given case, the denominator (x²-9) equals zero at x=±3, precisely what your teacher referred to.

When the denominator approaches zero, the function becomes infinite, and hence discontinuous.

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