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March 30, 2015

March 30, 2015

Posted by **Anonymous** on Tuesday, June 15, 2010 at 10:26pm.

s(t) = -4.9t^2 + 28t + 2.5

After how many seconds will the shell have the same speed, but be falling downward?

- Calculus -
**Reiny**, Tuesday, June 15, 2010 at 11:00pmv(t) = -9.8t + 28

we want this to be -28 (negative for downwards)

-9.8t + 28 = -28

-9.8t = -56

t = -56/-9.8 = 5.7 seconds

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