Tuesday

November 25, 2014

November 25, 2014

Posted by **Marisa** on Tuesday, June 15, 2010 at 3:49pm.

4x^2(PI)

My answer 4x^2(pi)=(pi)(r)(2), 16x(pi)=(pi)(r)(2), 16x/pi=5x.

5(PI)

My answer 5(pi)=(pi)(r)(2), sqare root of 5 is 2.23, which rounds to 3, 3(pi)=square root of 9.

What is the area of the sector if the radius is 6 and the degree measure is:

30

My answer 30/360(pi)(6)^2, 0.83(pi)(36),rounds to 1(pi).

50

My answer 50/360[(pi)6^2], 7.1/72[(pi)36], 7.1(36), 255/3.14, =81, square root of 81=9*pi.

90

My answer 90/360[(pi)6^2] 9.49/72[(pi)(36)], 18/9=2*pi.

120

My answer 120/360[(pi)6^2], 4/72[(pi)(36)] 4(36)=144, square root of 144=12*pi.

These are the question and answers that were incorrect on my assignment. I am unsure of what I did incorrect. I would be grateful for assistance. Cheers!

Sincerely,

Marisa

- Geometry -
**Reiny**, Tuesday, June 15, 2010 at 5:28pmfirst one:

πr^2 = 4x^2 π

r^2 = 4x2

r = 2x

if area = 5P

πr^2 = 5π

r^2 = 5

r = √5

sector angle=60°, r = 6

area = (30/360)(π)(36) = 3π

for sector angle=50°

area = (50/36)(36π) = 5π

the rest are the same

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