Calculate the theoretical yield of barium sulfate using your assigned volume. I was assigned 30mL of BaCl2. The balanced equation is: H2SO4 + BaCl2 -> 2HCl + BaSO4. In the experiment we used .20M BaCl2, .60M H2SO4 and 1M HCL
See above.
To calculate the theoretical yield of barium sulfate (BaSO4), you first need to convert the volume of BaCl2 you were assigned (30 mL) to the number of moles.
Step 1: Convert volume of BaCl2 to moles
To do this, you need to use the molarity of the BaCl2 solution.
Molarity (M) = moles/liters
Given:
Volume of BaCl2 (V) = 30 mL = 0.03 L
Molarity of BaCl2 (M) = 0.20 M
Rearranging the equation:
moles = Molarity × Volume
moles of BaCl2 = 0.20 M × 0.03 L
Now you have the moles of BaCl2 that you were assigned.
Step 2: Determine the stoichiometry
Based on the balanced equation: H2SO4 + BaCl2 -> 2HCl + BaSO4,
You can see that one mole of BaCl2 will produce one mole of BaSO4.
Step 3: Calculate the theoretical yield of BaSO4
Since the stoichiometry of BaSO4 and BaCl2 is 1:1, the moles of BaSO4 will be equal to the moles of BaCl2.
Theoretical yield of BaSO4 = Moles of BaCl2
Now you have calculated the theoretical yield of barium sulfate using the 30 mL volume of BaCl2 you were assigned.