Posted by **.** on Monday, June 14, 2010 at 4:13pm.

How do you factor this completely?

6x-x^3-x^2

- Math -
**Reiny**, Monday, June 14, 2010 at 5:00pm
6x-x^3-x^2

= -x(x^2 + x - 6)

= -x(x+3)(x-2)

- Math -
**Henry**, Monday, June 14, 2010 at 6:08pm
Factor 6X-X^3-X^2 completely.

Step1. Arrange exponents in decreasing order: -x^3-x^2+6x.

Step2.-X(X^2+X-6)

Step3. -X(X-2)(X+3).

The equation in step2 is not completely

factored, because the trinomial can be

factored into 2 binomials (step 3).

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