Please help! Evaluate the exponential equation for three positive values....?
Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Show your work
y=(1/4)^x+3
(1/4)^2 = 1/4 * 1/4 = 1/16
(1/4)^-2 = (reciprocal) 4^2 = 4 * 4 = 16
Any value to the 0 power = 1.
Use these principles for solving for the values you choose.
x=57
To evaluate the exponential equation for different values of x, substitute those values into the equation and simplify.
For positive values of x:
1. Let's start by evaluating the equation for x = 1.
Substitute x = 1 into the equation:
y = (1/4)^(1+3) = (1/4)^4 = 1/256
2. Now, let's evaluate for x = 2.
Substitute x = 2 into the equation:
y = (1/4)^(2+3) = (1/4)^5 = 1/1024
3. Finally, let's evaluate for x = 3.
Substitute x = 3 into the equation:
y = (1/4)^(3+3) = (1/4)^6 = 1/4096
So, for three positive values of x, we have:
y(x=1) = 1/256
y(x=2) = 1/1024
y(x=3) = 1/4096
Now let's evaluate the equation for three negative values of x:
1. For x = -1:
y = (1/4)^(-1+3) = (1/4)^2 = 1/16
2. For x = -2:
y = (1/4)^(-2+3) = (1/4)^1 = 1/4
3. For x = -3:
y = (1/4)^(-3+3) = (1/4)^0 = 1
So, for three negative values of x, we have:
y(x=-1) = 1/16
y(x=-2) = 1/4
y(x=-3) = 1
Finally, let's evaluate the equation when x = 0:
y = (1/4)^(0+3) = (1/4)^3 = 1/64
So, at x = 0, we have:
y(x=0) = 1/64
These are the values obtained by evaluating the exponential equation for three positive, three negative, and x=0 values.