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July 24, 2014

July 24, 2014

Posted by **Jinx007** on Sunday, June 13, 2010 at 9:29am.

A model helicopter of mass 5.0 kg rises with constant acceleration from rest to a height of 60 m in 10 seconds. Find the thrust exerted by the rotor blades during the ascent

- physics -
**MathMate**, Sunday, June 13, 2010 at 10:28amThrust required to keep the helicopter stationary

= weight of helicopter

= mg

To find the vertical (upwards) acceleration, we use the formula:

S=ut+(1/2)at²

where

S = distance = 60m

u = initial velocity = 0

t = time = 10 s

a=2(S-ut)/t²

=2(60-0)/10²

=1.2 m s^{-2}

Total thrust

= 5 kg ( 9.8 + 1.2 ) m s^{-2}

= 55 N

- physics -
**Alan Zamora**, Sunday, June 13, 2010 at 11:49amget a square root of spooky SAS 2 divided by the matrix of two plus two minus X multiply the eigen value of .23 electron volts equals macanca.

- physics -
**Juandissimo Hermiez**, Sunday, June 13, 2010 at 11:50amget a square root of spooky SAS 2 divided by the matrix of two plus two minus X multiply the eigen value of .23 electron volts equals macanca.

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