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December 19, 2014

December 19, 2014

Posted by **jenny** on Saturday, June 12, 2010 at 6:25pm.

- geometry-typo -
**MathMate**, Saturday, June 12, 2010 at 7:46pm"In triangle abc, point

**D**is on segment ab,...."

If you draw the diagram according to the corrected information, you will find that triangles BDE and BAC are similar.

Since AC:DE = AB:DB, therefore

AC=AB*DE/DB=(7+2)*3/2=13.5

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