Posted by amanda on Saturday, June 12, 2010 at 5:01pm.
For 1, pH = -log(H^+). Plug and chug. If you don't understand how to do this, explain your exact problem and I can help you through it. (It may be so simple that you just don't know how to handle the calculator.).
#2. No arrow. I don't know the reactants from the products. But the answer is to apply the Bronsted-Lowry theory of acids/bases.
Remember,
HA + H2O ==> H3O^+ + A^-
So HA is an acid because it donates a proton (to H2O) to form A^- (the conjugate base of HA) while H2O is a base (it accepts a proton from HA) and it forms the conjugate acid(H3O^+).
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