Choose whether the lines given below are parallel, perpendicular or neither. 4x - 6y = 9; 3x - 2y = 11

-6y+4x=9 -2y+3x=11
-6y=(9/-6)-(4/-6x) -2y=(11/-2)-(3/-2)
y=2/3x+-3/2 y=-3/2x+-11/2

so they would be perpendicular.
Is this right??

slope of 4x-6y=9 is 2/3

slope of 3x-2y = 11 is 3/2

so neither parallel nor perpendicular

for the equation
Ax + By + C = 0
the slope is - A/B

Thank you:)

Decide whether the pair of lines is parallel, perpendicular or neither: 2x+3y=3 2x+3y=10

To determine whether the lines are parallel, perpendicular, or neither, we need to compare their slopes.

The given lines are:
Line 1: 4x - 6y = 9
Line 2: 3x - 2y = 11

We can rewrite these equations in slope-intercept form (y = mx + b) to compare their slopes.

For Line 1:
4x - 6y = 9
-6y = -4x + 9
y = (4/6)x - 3/2
y = (2/3)x - 3/2

The slope of Line 1 is 2/3.

For Line 2:
3x - 2y = 11
-2y = -3x + 11
y = (3/2)x - 11/2

The slope of Line 2 is 3/2.

To determine whether the lines are parallel, perpendicular, or neither, we need to compare their slopes.

If the slopes of two lines are equal, then the lines are parallel.
If the slopes of two lines are negative reciprocals of each other (i.e., the product of the slopes is -1), then the lines are perpendicular.

Let's check the product of the slopes for Line 1 and Line 2:

(2/3) * (3/2) = 6/6 = 1

Since the product is not -1, the lines are neither parallel nor perpendicular.

So, in this case, you are incorrect in stating that the lines are perpendicular. They are neither parallel nor perpendicular.