posted by Anonymous .
A baseball leaves the bat with a speed of 44.0 m/s and an angle of 30.0 above the horizontal. A 10.0-m-high fence is located at a horizontal distance of 132 m from the point where the ball is struck. Assuming the ball leaves the bat 1.0 m above ground level, by how much does the ball clear the fence?
A) 4.4 m
B) 8.4 m
C) 13.4 m
D) 17.4 m
E) 18.4 m
The travel time to the fence is
T = 132 m/(Vo*cos 30) = 3.464 s
Vo = 44 m/s.
Write an equation for the height (y) of the ball vs time and determine its height at time T.
y = 1 + Vo*sin 30*T - (g/2)*T^2