IUPAC names for the following compounds please
1..............O
...............||
..........--...C
........./..\ /..\
.........\../.....H
..........--
2. ..............O
..................||
............CH3CH2-C-CH3
3..........CH3.O
...........|...||
.....CH3CH2CCH2C
................\
................OH
4............O
.............||
....CH3CH2CH2C
............. \
..............OCH2CH3
5..............O
.....--........||
..../..\-CH=CH-C-H
....\../
.....--
1. The IUPAC name for the first compound is 1-bromo-2-methylpropene.
To derive the IUPAC name:
- Locate the longest continuous carbon chain. In this case, it consists of 4 carbons.
- Number the carbons in the chain, starting from the end closest to the branch. In this case, we number from right to left, giving us carbon 1 at the branch attachment and carbon 4 at the end of the chain.
- Identify the substituents attached to the main chain. In this case, we have a bromine attached to carbon 1.
- Name the substituents alphabetically. In this case, since there is only one substituent, we simply name it as bromo.
- Combine the substituent name(s) with the parent chain name, separated by hyphens. In this case, the resulting IUPAC name is 1-bromo-2-methylpropene.
2. The IUPAC name for the second compound is 2-methylbutan-2-ol.
To derive the IUPAC name:
- Locate the longest continuous carbon chain. In this case, it consists of 4 carbons.
- Number the carbons in the main chain, starting from the end closest to the functional group. In this case, we number from left to right, giving us carbon 1 at the functional group attachment and carbon 4 at the end of the chain.
- Identify the substituents attached to the main chain. In this case, we have two methyl groups attached to carbon 2.
- Name the substituents alphabetically. In this case, since we have two methyl groups, we use the prefix di- and name them as dimethyl.
- Identify the functional group. In this case, the functional group is an alcohol (-OH) attached to carbon 2.
- Combine the substituent name(s), functional group name, and parent chain name, separated by hyphens. In this case, the resulting IUPAC name is 2-methylbutan-2-ol.
3. The IUPAC name for the third compound is 3-ethyl-4-methylhexan-2-one.
To derive the IUPAC name:
- Locate the longest continuous carbon chain. In this case, it consists of 6 carbons.
- Number the carbons in the main chain, giving priority to the carbonyl group (C=O) if present. In this case, we number from right to left, giving us carbon 2 at the carbonyl group, carbon 4 at the ethyl group attachment, and carbon 6 at the methyl group attachment.
- Identify the substituents attached to the main chain. In this case, we have an ethyl group attached to carbon 4 and a methyl group attached to carbon 6.
- Name the substituents alphabetically. In this case, we have an ethyl group and a methyl group, so we use the prefixes ethyl and methyl.
- Identify the functional group. In this case, the functional group is a ketone (-C=O) attached to carbon 2.
- Combine the substituent name(s), functional group name, and parent chain name, separated by hyphens. In this case, the resulting IUPAC name is 3-ethyl-4-methylhexan-2-one.
4. The IUPAC name for the fourth compound is propan-2-one.
To derive the IUPAC name:
- Locate the longest continuous carbon chain. In this case, it consists of 3 carbons.
- Number the carbons in the main chain, giving priority to the carbonyl group (C=O) if present. In this case, we number from left to right, giving us carbon 2 at the carbonyl group attachment and carbon 3 at the end of the chain.
- Identify the substituents attached to the main chain. In this case, we have an ethyl group attached to carbon 3.
- Name the substituents alphabetically. In this case, we have an ethyl group.
- Identify the functional group. In this case, the functional group is a ketone (-C=O) attached to carbon 2.
- Combine the substituent name(s), functional group name, and parent chain name, separated by hyphens. In this case, the resulting IUPAC name is propan-2-one.
5. The IUPAC name for the fifth compound is 2-chloro-2-butene.
To derive the IUPAC name:
- Locate the longest continuous carbon chain. In this case, it consists of 4 carbons.
- Number the carbons in the main chain, starting from the end closest to the double bond. In this case, we number from left to right, giving us carbon 2 at one end of the double bond and carbon 3 at the other end.
- Identify the substituent attached to the main chain. In this case, we have a chlorine atom attached to carbon 2.
- Name the substituent. In this case, we have a chlorine atom, so we name it as chloro.
- Identify the functional group. In this case, the functional group is the double bond (-CH=CH-) between carbons 2 and 3.
- Combine the substituent name, functional group name, and parent chain name, separated by hyphens. In this case, the resulting IUPAC name is 2-chloro-2-butene.