Posted by ill matic on Friday, June 11, 2010 at 2:59am.
coulombs = amperes x seconds.
C = 10A x 180 min x (60 s/min) = ??
It takes 96,500 coulombs to deposit 1 mol Cr/3 or 52.01/3 grams.
Why did you divide the molar mass by 3?
You would use stoichiometry. Multiply the amps by the time (convert minutes to seconds, then you end up with Coulombs. The stoichiometry should look a little like this...
(amps x time)(1 F/96,500 coulombs)(1 mol e-/1 F)(3 mol e-/1 mol Cr)(Molar Mass of Cr/1 mol Cr) ... I got the 3 mol e- from balancing the half-cell reactions. I got my answer to come out to 19.4 grams Cr
You would use stoichiometry. Multiply the amps by the time (convert minutes to seconds, then you end up with Coulombs. The stoichiometry should look a little like this...
(amps x time)(1 F/96,500 coulombs)(1 mol e-/1 F)(3 mol e-/1 mol Cr)(Molar Mass of Cr/1 mol Cr) ... I got the 3 mol e- from balancing the half-cell reactions. I got my answer to come out to 19.4 grams Cr
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