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January 25, 2015

January 25, 2015

Posted by **anna** on Friday, June 11, 2010 at 1:03am.

- math/Probability -
**Reiny**, Friday, June 11, 2010 at 6:37amLet's take a look at what we DON"T want

We do not want sums of 2, 3 and 4

sum of 2 -- 1 way

sum of 3 -- 2 ways

sum of 4 -- 3 ways , for a total of 6 we do not want

Since the two dice can fall in 36 ways,

30 of them would exceed a sum of 4

prob(your event) = 30/36 = 5/6

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