Posted by **bart** on Thursday, June 10, 2010 at 11:26pm.

Use the discriminant to determine how many real-number solutions the equation has.

36x2 - 12x + 1 = 0

How do I do this?

- Algebra HELP:( -
**Reiny**, Thursday, June 10, 2010 at 11:34pm
the discriminant is

b^2 - 4ac , namely the part under the √ sign of the quadratic formula

If it is positive, there are 2 different real solutions

if it is zero, there is one real answer

if it is negative, there are two complex solutions

If it is a perfect square, such as 36, there are 2 rational solutions.

so your discriminant

= 144 - 4(36)(1) = 0

mmmhhh?

- Algebra HELP. is this correct -
**bart**, Thursday, June 10, 2010 at 11:57pm
so 36 is 6,6 so there are two solutions. Am I understanding this correctly

- Algebra HELP:( -
**drwls**, Friday, June 11, 2010 at 12:04am
No, you aren't understanding it. The discriminant is zero, as reiuny has shown, so there is only one solution.

36x^2 - 12x + 1 = (6x -1)^2 = 0

Note that the polynomial is a perfect square. The only answer is x = 1/6

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