Algebra HELP:(
posted by bart .
Use the discriminant to determine how many realnumber solutions the equation has.
36x2  12x + 1 = 0
How do I do this?

the discriminant is
b^2  4ac , namely the part under the √ sign of the quadratic formula
If it is positive, there are 2 different real solutions
if it is zero, there is one real answer
if it is negative, there are two complex solutions
If it is a perfect square, such as 36, there are 2 rational solutions.
so your discriminant
= 144  4(36)(1) = 0
mmmhhh? 
so 36 is 6,6 so there are two solutions. Am I understanding this correctly

No, you aren't understanding it. The discriminant is zero, as reiuny has shown, so there is only one solution.
36x^2  12x + 1 = (6x 1)^2 = 0
Note that the polynomial is a perfect square. The only answer is x = 1/6