Posted by Ana on Thursday, June 10, 2010 at 11:16pm.
you could do ....
sinx/cosx + cosx/sinx
= (sin^2x + cos^2x)/(sinxcosx)
= 1/[ (1/2)2sinxcosx ]
= 1/((1/2)sin 2x)
= 2/sin2x or 2csc 2x
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