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November 28, 2014

November 28, 2014

Posted by **Miguel** on Thursday, June 10, 2010 at 10:01pm.

- Precalculus -
**Reiny**, Thursday, June 10, 2010 at 11:22pmsolve

.57 = 1(1/2)^(t/5730)

log both sides

log .57 = log (.5)^(t/5730)

log .57 = t/5730 (log .5)

t/5730 = log .57/log .5

t/5730 = .810966

t = 4646.8

appr. 4647 years

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