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September 18, 2014

September 18, 2014

Posted by **Kris** on Thursday, June 10, 2010 at 6:24pm.

- Algebra -
**Damon**, Thursday, June 10, 2010 at 7:29pmTwo ways to do it:

each year multiply by 1.015 (like compound interest)

1.015^n = 2

n log 1.015 = log 2

n = log 2 / log1.015 = 46.55 years

or do it the way they said to do it with continuous growth

dy/dt = .015y

y = yi e^.015 t

y/yi = 2 = e^.015 t

ln 2 = .015 t

t = 46.2

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